• NeatNit@discuss.tchncs.de
    link
    fedilink
    English
    arrow-up
    3
    ·
    3 months ago

    I don’t get it, and the world’s quickest and last comprehensive DDG search didn’t find an explanation either.

    • Kogasa@programming.dev
      link
      fedilink
      English
      arrow-up
      4
      ·
      3 months ago

      It’s a reach, but the Fourier transformation of a Schwarz (rapidly decaying) function is also a Schwarz function. Compact support is a strictly stronger condition than Schwarz (the function must eventually decay to 0) but doesn’t have this nice property with respect to Fourier transforms, i.e. the FT of a compactly supported function is Schwarz but not necessarily compactly supported